-4=-16t^2+325t

Solution for -4=-16t^2+325t equation:

-4=-16t^2+325t

We move all terms to the left:

-4-(-16t^2+325t)=0

We get rid of parentheses

16t^2-325t-4=0

a = 16; b = -325; c = -4;
Δ = b2-4ac
Δ = -3252-4·16·(-4)
Δ = 105881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-325)-\sqrt{105881}}{2*16}=\frac{325-\sqrt{105881}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-325)+\sqrt{105881}}{2*16}=\frac{325+\sqrt{105881}}{32}
$